#### Pipe and Cistern concept

**Concept | Practice set 1 | Practice set 2**

**Download Concept as a pdf form click below link**

### Pipes and Cisterns Shortcut Methods

**Pipe and Cistern problems are similar to time and work problems. A pipe is used to fill or empty the tank or cistern.**

**What is Inlet Pipe:** A pipe used to fill the tank or cistern is known as Inlet Pipe.

**What is Outlet Pipe:** A pipe used to empty the tank or cistern is known as Outlet Pipe.

**Pipes and Cisterns Shortcut Formulas**

**Pipes and Cisterns Formula 1:**

Two pipes can fill (or empty) a cistern in x and y hours while working alone. If both pipes are opened together, then the time taken to fill (or empty) the cistern is given by (xy/(x+y)) hours

**Pipes and Cisterns Formula 2:**

Three pipes can fill (or empty) a cistern in x, y and z hours while working alone. If all the three pipes are opened together, the time taken to fill (or empty) the cistern is given by (xyz/(xy+yz+zx))hours

**Pipes and Cisterns Formula 3:**

If a pipe can fill a cistern in x hours and another can fill the same cistern in y hours, but a third one can empty the full tank in z hours, and all of them are opened together, then

Net Part filled in 1 hour = 1/x + 1/y – 1/z

Time taken to fill the full cistern = xyz/(yz+xz-xy)

**Pipes and Cisterns Formula 4:**

A pipe can fill a cistern in x hours. Because of a leak in the bottom, it is filled in y hours. If it is full, the time taken by the leak to empty the cistern is

xy/(y-x) hours

**Pipes and Cisterns basic formulas:**

If an inlet pipe can fill the tank in x hours, then the part filled in 1 hour = 1/x

If an outlet pipe can empty the tank in y hours, then the part of the tank emptied in 1 hour = 1/y

If both inlet and outlet valves are kept open, then the net part of the tank filled in 1 hour is 1/x-1/y

**Pipes and Cisterns Question 1**

Two pipes A and B can fill a tank in 20 and 30 minutes respectively. If both the pipes are used together, then how long will it take to fill the tank?

Step1: Take L.C.M for 20 and 30

Step2: Tank capacity (L.C.M) is 60

Every min pipe A fill 3 part of the tank (60/20=3)

Every min pipe B fill 2 part of the tank (60/30=2)

Together filling so (3+2=5) 5 part of the tank is filling at Every min 12*5=60

Totally 60(L.C.M) parts will be fill in 12 minutes

**Pipes and Cisterns Question 2**

Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?

Ans : 6/11

**Pipes and Cisterns Question 3**

Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:

Ans : 60/17 Hours

**Pipes and Cisterns Question 4 **

A pipe can fill a tank in 3 hours. Because of leak in the bottom, it is filled in 4 hours. If the tank is full, how much time will the leak take to empty it?

Pipes and Cisterns 1/3-1/4 =1/12

So leak will empty the tank in 12 hours.

(Apply this formula xy/(y-x) ans 12 hours)

**Pipes and Cisterns Problem 5**

Two pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, Pipe A is turned off. What is the total time required to fill the tank ?

Solution :Part of tank filled by A + B in 1 minute = ( 1 / 15 + 1 / 20 )

So tank filled by A + B in 4 minute = 4 ( 1 / 15 + 1 / 20 ) = 7 / 15

Part remaning = 1 – ( 7 / 15 ) = 8 / 15

1 / 20 part is filled by B in 1 minute

So, 8 / 15 part will be filled in = ( 20 / 1 )* ( 8 / 15 ) = 32 / 3 = 10 minutes 40 sec.

**Pipes and Cisterns Problem 6**

A cistern is normally filled in 8 hrs, but it takes four hrs longer to fill beacuse of a leak in the bottom. If the cistern is full , how much time the leak will empty it ?

Solution : Let the leak will empty the tank in x hrs.

Then part of cistern filled in 1 hr = ( 1 / 8 ) – ( 1 / x ) = x – 8 / 8x

So cistern will completly filled in 8x / x – 8

Ans : 24 hours

**Pipes and Cisterns Problem 7**

A tank is normally filled in 8 hrs. but takes 2 hrs.longer to fill because of leak in its bottom. If the cistern is full, in how many hours will the leak empty it?

Solution: When leak doesn’t work the tank is filled in 8 hrs.

When both filler pipe and leak work together, the tank is filled in 8+2 = 10 hrs.

Therefore, the time taken by leak to empty the tank = 8*10/ (10-8) = 40 Hours

**Pipes and Cisterns Problem 8**

A tank has a leak which would empty it in 8 hrs. A tap is turned on which admits 6 liters a minute in to the tank, and it is now emptied in 12 hrs. How many liters does the tank hold?

Solution: The time taken to fill the tank 12*8/(12-8) = 24 hours

**Pipes and Cisterns Problem 9**

An electric pump can fill a tank in 3 hours. Because of a leak in the tank, it took 3 (1/2)hours to fill the tank. If the tank is full, how much time will the leak take to empty it ?

Work done by the leak in 1 hour =[(1/3)-(1/(7/2))=1/3-7/2=1/21

The leak will empty the tank in 21 hours.