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No. of Questions 
10 
Time 
10 min 
Medium 
english 
Marks 
10 
Positive Marks 
+1 
Negative Marks 
0 
INSTRUCTION : All question carry 1 mark and there is only single option correct for every questionMark review to see the question later 
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Question 1 of 10
1. Question
1 pointsA right triangle with sides 3 cm, 4 cm and 5 cm is rotated the side of 3 cm to form a cone. The volume of the cone so formed is:
Correct
Incorrect
A right triangle with sides 3 cm, 4 cm and 5 cm is rotated the side of 3 cm to form a cone. The volume of the cone so formed is: A. 12 cm^{3} B. 15 cm^{3} C. 16 cm^{3} D. 20 cm^{3} Answer: Option A
Explanation:
Clearly, we have r = 3 cm and h = 4 cm.
Volume = 1 r^{2}h = 1 x x 3^{2} x 4 cm^{3} = 12 cm^{3}. 3 3 
Question 2 of 10
2. Question
1 pointsIn a shower, 5 cm of rain falls. The volume of water that falls on 1.5 hectares of ground is:
Correct
Answer: Option B
Explanation:
1 hectare = 10,000 m^{2}
So, Area = (1.5 x 10000) m^{2} = 15000 m^{2}.
Depth = 5 m = 1 m. 100 20 Volume = (Area x Depth) = 15000 x 1 m^{3} = 750 m^{3}. 20 Incorrect
Answer: Option B
Explanation:
1 hectare = 10,000 m^{2}
So, Area = (1.5 x 10000) m^{2} = 15000 m^{2}.
Depth = 5 m = 1 m. 100 20 Volume = (Area x Depth) = 15000 x 1 m^{3} = 750 m^{3}. 20 
Question 3 of 10
3. Question
1 pointsA hall is 15 m long and 12 m broad. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, the volume of the hall is:
Correct
Answer: Option C
Explanation:
2(15 + 12) x h = 2(15 x 12)
h = 180 m = 20 m. 27 3 Volume = 15 x 12 x 20/3 m^{3} = 1200 m^{3}. Incorrect
Answer: Option C
Explanation:
2(15 + 12) x h = 2(15 x 12)
h = 180 m = 20 m. 27 3 Volume = 15 x 12 x 20/3 m^{3} = 1200 m^{3}. 
Question 4 of 10
4. Question
1 points66 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be:
Correct
Answer: Option A
Explanation:
Let the length of the wire be h.
Radius = 1 mm = 1 cm. Then, 2 20 22 x 1 x 1 x h = 66. 7 20 20 h = 66 x 20 x 20 x 7/22 = 8400 cm = 84 m. Incorrect
Answer: Option A
Explanation:
Let the length of the wire be h.
Radius = 1 mm = 1 cm. Then, 2 20 22 x 1 x 1 x h = 66. 7 20 20 h = 66 x 20 x 20 x 7/22 = 8400 cm = 84 m. 
Question 5 of 10
5. Question
1 pointsA hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3, then the weight of the pipe is:
Correct
Answer: Option B
Explanation:
External radius = 4 cm,
Internal radius = 3 cm.
Volume of iron = 22 x [(4)^{2} – (3)^{2}] x 21 cm^{3} 7 = 22 x 7 x 1 x 21 cm^{3} 7 = 462 cm^{3}. Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.
Incorrect
Answer: Option B
Explanation:
External radius = 4 cm,
Internal radius = 3 cm.
Volume of iron = 22 x [(4)^{2} – (3)^{2}] x 21 cm^{3} 7 = 22 x 7 x 1 x 21 cm^{3} 7 = 462 cm^{3}. Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.

Question 6 of 10
6. Question
1 pointsA boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:
Correct
Answer: Option B
Explanation:
Volume of water displaced = (3 x 2 x 0.01) m^{3} = 0.06 m^{3}. Mass of man = Volume of water displaced x Density of water = (0.06 x 1000) kg = 60 kg. Incorrect
Answer: Option B
Explanation:
Volume of water displaced = (3 x 2 x 0.01) m^{3} = 0.06 m^{3}. Mass of man = Volume of water displaced x Density of water = (0.06 x 1000) kg = 60 kg. 
Question 7 of 10
7. Question
1 points50 men took a dip in a water tank 40 m long and 20 m broad on a religious day. If the average displacement of water by a man is 4 m3, then the rise in the water level in the tank will be:
Correct
Answer: Option B
Explanation:
Total volume of water displaced = (4 x 50) m^{3} = 200 m^{3}.
Rise in water level = 200 m 0.25 m = 25 cm. 40 x 20 Incorrect
Answer: Option B
Explanation:
Total volume of water displaced = (4 x 50) m^{3} = 200 m^{3}.
Rise in water level = 200 m 0.25 m = 25 cm. 40 x 20 
Question 8 of 10
8. Question
1 pointsThe slant height of a right circular cone is 10 m and its height is 8 m. Find the area of its curved surface.
Correct
Answer: Option C
Explanation:
l = 10 m,
h = 8 m.
So, r = sqrt(l^{2} – h^{2} )= sqrt{(10)^{2} – 8^{2}} = 6 m.
Curved surface area = rl = ( x 6 x 10) m^{2} = 60 m^{2}
Incorrect
Answer: Option C
Explanation:
l = 10 m,
h = 8 m.
So, r = sqrt(l^{2} – h^{2} )= sqrt{(10)^{2} – 8^{2}} = 6 m.
Curved surface area = rl = ( x 6 x 10) m^{2} = 60 m^{2}

Question 9 of 10
9. Question
1 pointsA cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:
Correct
Answer: Option A
Explanation:
Area of the wet surface = [2(lb + bh + lh) – lb]
= 2(bh + lh) + lb
= [2 (4 x 1.25 + 6 x 1.25) + 6 x 4] m2
= 49 m2Incorrect
Answer: Option A
Explanation:
Area of the wet surface = [2(lb + bh + lh) – lb]
= 2(bh + lh) + lb
= [2 (4 x 1.25 + 6 x 1.25) + 6 x 4] m2
= 49 m2 
Question 10 of 10
10. Question
1 pointsA metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m3) is:
Correct
Answer: Option B
Explanation:
Clearly, l = (48 – 16)m = 32 m,
b = (36 16)m = 20 m,
h = 8 m.
Volume of the box = (32 x 20 x 8) m3 = 5120 m3.
Incorrect
Answer: Option B
Explanation:
Clearly, l = (48 – 16)m = 32 m,
b = (36 16)m = 20 m,
h = 8 m.
Volume of the box = (32 x 20 x 8) m3 = 5120 m3.